(4(e^1-2x))-(9(e^4-3x))=0

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Solution for (4(e^1-2x))-(9(e^4-3x))=0 equation:


Simplifying
(4(e + -2x)) + -1(9(e4 + -3x)) = 0
((e * 4 + -2x * 4)) + -1(9(e4 + -3x)) = 0
((4e + -8x)) + -1(9(e4 + -3x)) = 0
(4e + -8x) + -1(9(e4 + -3x)) = 0

Remove parenthesis around (4e + -8x)
4e + -8x + -1(9(e4 + -3x)) = 0
4e + -8x + -1((e4 * 9 + -3x * 9)) = 0
4e + -8x + -1((9e4 + -27x)) = 0
4e + -8x + (9e4 * -1 + -27x * -1) = 0
4e + -8x + (-9e4 + 27x) = 0

Reorder the terms:
4e + -9e4 + -8x + 27x = 0

Combine like terms: -8x + 27x = 19x
4e + -9e4 + 19x = 0

Solving
4e + -9e4 + 19x = 0

Solving for variable 'e'.

The solution to this equation could not be determined.

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